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þ ðkd k JÑ René Descartes, 1637 Ô I 2. Gottfried Leibniz å vis viva...

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n˘ ˘ ¯U¯ Ø> œ˘nX!œCn¥% u˜¯˜U¯{/ ˜¯kd(kJ ¯ i m i v 2 i ¯ 1gr U ƒ^ c§ [ª5-EK Lª˜U¯ mv 2 m~v ¯ §Y ıc Vˇ§^¯ı/0§rN/ı0Vg ¯U£¯/ ¯U£¯/ ƒ/U ˜Un ı Un :X˜Un U U k% ¯U U $˜5 ¯U¯˘ :X¯U¯˘ ¯XmüC5 üNK %XZFn ZFn %X¥.5/ı -E - - %X¥-E Ø¡5¯˘ Ø¡5¯˘ ¯U£¯/ ˚ˇ{˜¤{ -→ 3,«C 1(7$˜ §~v C§ | ~v| C 1 2 mv 2 C -→ ˜U·¯ ¥eEa˜ ¥9v v = p 2g(h 0 - z )§,!eü( 1 2 mv 2 2¯§ 1 2 mv 2 + mgz = mgh 0 U ˜U U p=
Transcript
Page 1: þ ðkd k JÑ René Descartes, 1637 Ô I 2. Gottfried Leibniz å vis viva …zimp.zju.edu.cn/~qchen/Teaching/Mechanics/Handout4.pdf · 2017-11-02 · Question: Big bang §t= 0 žU

ÔnÆ I � åÆ�Chap.4 Å�UÅð

Qijin Chen �é>

Department of Physics, Zhejiang University

úô�ÆÔnX!úôC�Ôn¥%

September 19, 2013

Copyright c©2013 by Qijin Chen; all rights reserved.

'uÄþÅðÚÄUÅð�{¤�Ø

1. ÄþÅðkd(k�JÑ René Descartes, 1637

2. Gottfried Leibniz → ¹å vis viva Åð (During 1676-1689)

living force∑imiv

2i Åð

Thomas Young, 1807 : 1�gr vis viva ��Uþ(energy)¦^

1703c§Huygens �[�ã�5-E¯K↓

��LãÄUÅð

mv2 Ú m~v Åð��§±Y100õc⇓

Two independent laws, both are right

19­VÐϧ^Å�õÿ/¹å0§rN/õ0�Vg

Outline

1 Å�U£Åð¤Å�U£Åð¤Ù¦/ª�³U

2 ÄU½nõ Work

�:ÄU½n�:XÄU½n

3 ³UÚå³U(k%å)

�Åå�³U³U­���$Ä���5�

4 Å�UÅð½Æ�:XÅ�UÅð½Æ�ÅX��m�üØC5üN¯K

5 �%X��ZF½n�ZF½n�%X¥.5å¤��õ

6 -E�-�-�%X¥�-E

7 é¡5�Åð½Æé¡5�Åð½Æ

Å�U£Åð¤

ØʱÏ{Ä�¨{ −→ �3,«ØCþ

1(7���±$ħ~v C§� |~v| ØC1

2mv2 ØC = const. −→ ÄU´Åðþ

®¥þe­EaÄ®¥� �9�Ý÷v

v =√

2g(h0 − z)§þ,!eüÑ�(1

2mv2Ø2Åð§�

1

2mv2 +mgz = mgh0=const.

↑­å³U

ÄU ↔ ³U �p=�

Page 2: þ ðkd k JÑ René Descartes, 1637 Ô I 2. Gottfried Leibniz å vis viva …zimp.zju.edu.cn/~qchen/Teaching/Mechanics/Handout4.pdf · 2017-11-02 · Question: Big bang §t= 0 žU

Å�U£Åð¤ (cont'd)

Am

mW

z

O

0hXm㧭ÔWlh0?.X31wS¡þ�ÔNA�å$Ä"

Щµt = 0 �§W uz = h0, v0 = 0

=⇒ v =m

m+mAgt, z = h0−

1

2

m

m+mAgt2, (a =

mg

m+mA)

1

2mv2 +mgz = mgh0 −

1

2mAa

2t2 6= const.

�A�öħ1

2mAv

2 =1

2mAa

2t2

∴1

2mv2 +mgz +

1

2mAv

2 = mgh0 = const.

� ÔÔÔNNNA���WmmmUUUþþþ���===£££§§§���oooUUUØØØCCC

Å�U£Åð¤ (cont'd)

½½½ÂµµµT =

1

2mv2 � Kinetic energe, KE

3­å|¥§­å³U V = mgz

ÔNNX�ÄU�³U�Ú¡�Å�U

ÅÅÅ���UUUÅÅÅððð:

E = T + V = const.

Uþþjµ[E] = ML2T−2

ü µ1 J = 1 kg ·m2/s2 = 1 N ·m

Å�U£Åð¤ (cont'd)

ÅÅÅ���UUUÅÅÅððð333éééõõõ���ÿÿÿØØؤ¤¤ááá

~µ1 k�Þ�§~f ‖ −~v −→ Uþ���9U9UáSU§3�*��f!©f�ÄU

T + V +SU = const.

2 zÆUX�¿�A

3 ØU!>^U�=�3Å�U�Ù¦/ª�Uþ�p=z�§T + VØÅð

Outline

1 Å�U£Åð¤Å�U£Åð¤Ù¦/ª�³U

2 ÄU½nõ Work

�:ÄU½n�:XÄU½n

3 ³UÚå³U(k%å)

�Åå�³U³U­���$Ä���5�

4 Å�UÅð½Æ�:XÅ�UÅð½Æ�ÅX��m�üØC5üN¯K

5 �%X��ZF½n�ZF½n�%X¥.5å¤��õ

6 -E�-�-�%X¥�-E

7 é¡5�Åð½Æé¡5�Åð½Æ

Page 3: þ ðkd k JÑ René Descartes, 1637 Ô I 2. Gottfried Leibniz å vis viva …zimp.zju.edu.cn/~qchen/Teaching/Mechanics/Handout4.pdf · 2017-11-02 · Question: Big bang §t= 0 žU

Ù¦/ª�³U

ÄU�k�«/ª§³Ukéõ«

m

0x

���555³³³UUUµ���x0§\­Ô����x0 + h

Hook's law: f = −k (x− x0)

mg − k (x− x0) = mdv

dt= m

dv

dx

dx

dt= m

dv

dxv =

1

2

d

dx

(mv2

)∫ x0+h

x0

:1

2mv2

∣∣∣∣v=0

v=0

=

[mgx− 1

2k (x− x0)2

]∣∣∣∣x0+h

x0

= mgh−1

2kh2

∴ mgh = 12kh

2 ­å³U��5³Um=�↑

�5³UEp =

1

2kh2 =

1

2k (x− x0)2

�áX �«/ªUþ�oÚÅð ←− �m²£ØC5Question: Big bang§t = 0 �UþÅðíº

Outline

1 Å�U£Åð¤Å�U£Åð¤Ù¦/ª�³U

2 ÄU½nõ Work

�:ÄU½n�:XÄU½n

3 ³UÚå³U(k%å)

�Åå�³U³U­���$Ä���5�

4 Å�UÅð½Æ�:XÅ�UÅð½Æ�ÅX��m�üØC5üN¯K

5 �%X��ZF½n�ZF½n�%X¥.5å¤��õ

6 -E�-�-�%X¥�-E

7 é¡5�Åð½Æé¡5�Åð½Æ

õ Work

½Â�:ÄU�CzL§�£å3¤�õ

A = T2 − T1 = W

�¦�:ÄU±T1C�T2§I�õW

T2 = W + T1

�� £2¤UþÅð§W´Uþ��«

W > 0§��õ¶W < 0§�Kõ

²þõÇ 〈P 〉 =T2 − T1

t2 − t1=

∆T

∆t

]�õÇ P =dT

dt= lim

∆t→0

∆T

∆t

õÚõÇ: ���/

�Ä����$ħ�:3å F �^e\�

mdv

dt= F

v× :1

2m

dv2

dt= Fv =

dT

dt= P�� ��P = Fv

W =

∫ t2

t1

Pdt =

∫ t2

t1

Fdx

dtdt =

∫ x2

x1

Fdx

W =

∫Pdt =

∫Fdx

O 1x 2x 3x

=⇒ �õ�9�L§ =⇒ õ´ÝþL§�Ônþ§ØU½Â,��]�½,�:�õ

XÔN3å��^ed x1 � x3 2� x2§ØU�È© x1 � x2

Page 4: þ ðkd k JÑ René Descartes, 1637 Ô I 2. Gottfried Leibniz å vis viva …zimp.zju.edu.cn/~qchen/Teaching/Mechanics/Handout4.pdf · 2017-11-02 · Question: Big bang §t= 0 žU

õÚõÇ: 3D �/

ííí222��� 3D case

md~v

dt= ~F

m~v · d~v

dt= ~F · ~v

d

dt

(1

2m~v2

)= ~F · ~v =

d

dtT = P�� ��P = ~F · ~v

W =

∫ t2

t1

Pdt =

∫ t2

t1

~F · ~vdt =

∫ ~x2

~x1

~F · d~x

(l)←÷;,È©

∆W = ~F ·∆~r = F∆s cos θ θ =(~F ,∆~r

)Y�

R�u$Ä��Ø�õ~Fcor = −2m~ω × ~v′ ⊥ ~v′, Ø�õ

Outline

1 Å�U£Åð¤Å�U£Åð¤Ù¦/ª�³U

2 ÄU½nõ Work

�:ÄU½n�:XÄU½n

3 ³UÚå³U(k%å)

�Åå�³U³U­���$Ä���5�

4 Å�UÅð½Æ�:XÅ�UÅð½Æ�ÅX��m�üØC5üN¯K

5 �%X��ZF½n�ZF½n�%X¥.5å¤��õ

6 -E�-�-�%X¥�-E

7 é¡5�Åð½Æé¡5�Åð½Æ

�:ÄU½n

�^uÔNþ�Üå¤��õ�udL§¥ÄU�Oþ��

� W =

∫ ~r

~r0

~F · d~r = EK − EK0 = T − T0

~F · d~r � �õ

P =dT

dt=

dW

dt= ~F · ~v

õ�ü  J: 1 J �u 1 N �åí£ 1 m�´§¤��õ§õÇ1 W = 1 J/s

>þ ݵ103 W · h = Z�� = 3.6× 106 J

Outline

1 Å�U£Åð¤Å�U£Åð¤Ù¦/ª�³U

2 ÄU½nõ Work

�:ÄU½n�:XÄU½n

3 ³UÚå³U(k%å)

�Åå�³U³U­���$Ä���5�

4 Å�UÅð½Æ�:XÅ�UÅð½Æ�ÅX��m�üØC5üN¯K

5 �%X��ZF½n�ZF½n�%X¥.5å¤��õ

6 -E�-�-�%X¥�-E

7 é¡5�Åð½Æé¡5�Åð½Æ

Page 5: þ ðkd k JÑ René Descartes, 1637 Ô I 2. Gottfried Leibniz å vis viva …zimp.zju.edu.cn/~qchen/Teaching/Mechanics/Handout4.pdf · 2017-11-02 · Question: Big bang §t= 0 žU

�:XÄU½n

mi~ri = ~Fi +∑j 6=i

~fji

∫ t

t0

·~vidt :

∫ t

t0

mi~vi · ~vidt =

∫ t

t0

~Fi · ~vidt+∑j 6=i

∫ t

t0

~fji · ~vidt

=

∫ t

t0

1

2d(mi~v

2i

)

=⇒ Ti (t)− Ti (t0) = Wi +∑j 6=i

Wji

Wi =

∫ t

t0

~Fi · ~vidt =

∫ xi

xi0

~Fi · d~xi

Wji =

∫ t

t0

~fji · ~vidt

�:XÄU½n (cont'd)

∑i

[Ti (t)− Ti (t0)] =∑iWi +

∑i,j 6=i

Wji

=⇒ T − T (t0) = W +WS �� �:XÄU½n

T =∑iTi, W =

∑iWi, WS =

∑i,j 6=i

Wji

5¿WS�Ñy§��:Äþ½nØÓd?Så�ØUCoÄþ§�O\�õ�ϵÄþ�¥þ§ÄU£õ¤´Iþå�Så�õ�Ú�u�:XÄU�Oþ�:XÄþ½nÚõU½n�pÕá

~~~4.1 m = 10�§v0 = 200 m/s§�\7¬§²þ{åF = 5× 103 N, ¦\��Ý.

E1 =1

2mv0

2 = Fs =⇒ s =mv0

2

2F= 0.04 m

Outline

1 Å�U£Åð¤Å�U£Åð¤Ù¦/ª�³U

2 ÄU½nõ Work

�:ÄU½n�:XÄU½n

3 ³UÚå³U(k%å)

�Åå�³U³U­���$Ä���5�

4 Å�UÅð½Æ�:XÅ�UÅð½Æ�ÅX��m�üØC5üN¯K

5 �%X��ZF½n�ZF½n�%X¥.5å¤��õ

6 -E�-�-�%X¥�-E

7 é¡5�Åð½Æé¡5�Åð½Æ

Úå³U

­å³U mgz

M 1rrm

1 3

2

5

4�kÚå ~F = −GmM

r2r

1→ 2 : W = A = ~F ·∆~r = −GmMr1

2∆r

�� ���Ã'

1→ 3 : A = ~F · d~r =GmM

r12

∆r

cos θcos (π − θ) = −GmM

r12

∆r

4→ 5 �Óu 1→ 2

�kÚå�õ§��Ð!"�ålk'§���Ã'=�´»Ã'

a→ b : A =

∫(l)

~F · d~r =

∫ rb

ra

~F · d~r = −∫ rb

ra

GmM

r2dr

=GmM

rb− GmM

ra= Tb − Ta

Page 6: þ ðkd k JÑ René Descartes, 1637 Ô I 2. Gottfried Leibniz å vis viva …zimp.zju.edu.cn/~qchen/Teaching/Mechanics/Handout4.pdf · 2017-11-02 · Question: Big bang §t= 0 žU

Úå³U

Ta +

(−GmM

ra

)= Tb +

(−GmM

rb

)= const.

V = −GmMr

��Úå³U

Úå�k%å§4Ü´»�õ�". ← é ∀ k%å¤á

k%å ~F (~r) = F (r) r

´»Lþ?��� ds = KM , k

dA = ~F ·−−→KM = F (rk) ds cos θ

= F (rk′)K ′M ′ →ÝK�,�»���þ

A =

∫ Q

PdA =

∫ Q′

PF (r) dr =

∫ rQ

rP

F (r) dr, ���»k',�´»Ã'

=⇒∮

~F · d~r = 0

Outline

1 Å�U£Åð¤Å�U£Åð¤Ù¦/ª�³U

2 ÄU½nõ Work

�:ÄU½n�:XÄU½n

3 ³UÚå³U(k%å)

�Åå�³U³U­���$Ä���5�

4 Å�UÅð½Æ�:XÅ�UÅð½Æ�ÅX��m�üØC5üN¯K

5 �%X��ZF½n�ZF½n�%X¥.5å¤��õ

6 -E�-�-�%X¥�-E

7 é¡5�Åð½Æé¡5�Åð½Æ

�Åå

Úå9k%å�õ�´»Ã'§��Þ�´»k'y

O

1y

2y2 3

1

x

Xmã§1→ 2 gdáN

­åõµAG1→2 = mg (y1 − y2)

FrictionµAf1→2 = 0

1→ 3 : AG1→3 = mg

y1 − y2

cos θ· cos θ = mg (y1 − y2)

Af1→3 = µmg sin θ

y1 − y2

cos θcosπ

= −µmg (y1 − y2) tan θ

3→ 2 : AG3→2 = 0

Af3→2 = (y1 − y2) tan θ · µmg cosπ = −µmg (y1 − y2) tan θ

=⇒ AG1→3 +AG

3→2 = AG1→2

Af1→3 +Af

3→2 = −2µmg (y1 − y2) tan θ 6= Af1→2

�Åå (cont'd)

XJå��õ�´»Ã'§��Ð": �k' −→ �Åå

é�Åå§�½Â¼ê

V (rb) = Va −Aa→b, Va�T¼ê3a??À�ê�

V (r) ¡�³U¼ê=⇒ Aa→b = Va − Vb∵ Aa→b = Tb − Ta

=⇒ Ta + Va = Tb + Vb = const.

∴ �ÅåX¥§Å�UÅð

�L5If Ta + Va = Tb + Vb = const., (∀a, b)

=⇒ Tb − Ta = Va − Vb = Aa→b

K Aa→b = Va − Vb �´»Ã' =⇒ �Åå

Page 7: þ ðkd k JÑ René Descartes, 1637 Ô I 2. Gottfried Leibniz å vis viva …zimp.zju.edu.cn/~qchen/Teaching/Mechanics/Handout4.pdf · 2017-11-02 · Question: Big bang §t= 0 žU

�Åå (cont'd)

=⇒ Å�UÅð (T + V = const.) ´NX¥��3�Åå�¿�^�§´³UVg·^�¿�^�.[

é��Ååµ~f · d~r ≤ 0, ÑÑå§Å�U~�~f · d~r ≥ 0, Å�UO\

]

V (~r) = −∫ r

r0

~F · d~r + V0

~F (~r) = −~∇V (~r) =

(i∂V

∂x+ j

∂V

∂y+ k

∂V

∂z

)Úå³

~F = −GmMr2

r

� V (r =∞) = 0

V (~r) = −∫ r

∞~F · d~r =

∫ r

+∞GMm

r2dr= −GMm

r

⇐⇒ ~F = −~∇V (r) = −GmMr2

r

�Åå (cont'd)

5¿µ1 Úå³U�m,M�ö�k§�3Äþ¥%X¥

m~v +M~V = 0 =⇒ 1

2mv2 � 1

2MV 2

ÄUÌ��m¤k§T + V Åð�¦ M �Czé�2

A (~r0 − ~r) = V (r0)− V (r) = Tr − T0

= − [V (r)− V (r0)]

�Åå�õ¦³U~�

3 XJNX¥�k�Åå§K��ÅNX4 ØÓ�ÅåÚå�³U��\

Outline

1 Å�U£Åð¤Å�U£Åð¤Ù¦/ª�³U

2 ÄU½nõ Work

�:ÄU½n�:XÄU½n

3 ³UÚå³U(k%å)

�Åå�³U³U­���$Ä���5�

4 Å�UÅð½Æ�:XÅ�UÅð½Æ�ÅX��m�üØC5üN¯K

5 �%X��ZF½n�ZF½n�%X¥.5å¤��õ

6 -E�-�-�%X¥�-E

7 é¡5�Åð½Æé¡5�Åð½Æ

³U­�

å´¥þ§³U´Iþ§�´(½§��B��³U¼ê=�³U­�

地表重力 引力,库仑力

V V

O z

mgz cr

r

2

cr

rF F

mg

O

O O

Page 8: þ ðkd k JÑ René Descartes, 1637 Ô I 2. Gottfried Leibniz å vis viva …zimp.zju.edu.cn/~qchen/Teaching/Mechanics/Handout4.pdf · 2017-11-02 · Question: Big bang §t= 0 žU

³U­�

弹性势能 双原子分子

V V

O

O

OO

r

r

FF

x

x

212

kx

kx

0r

0r

1 ~F = −~∇V → d³¦å2 V (r) → ¦²ï �!­½5©Û

~: /¥Úå��<º�Ý

0E

0E

V

maxr

V引

rE =

1

2mv2 − GmM

r= const.

�E < 0, rmax =GmM

−E, åP$Ä

�E > 0, v > 0, ∀r, � gd$Ä

1

2mv2−GmM

r= 0 =⇒ v =

√2GME

R=√

2gR ' 11.2 km/s2

(g =

GME

R2

)

~: �E&�

�EÅ�UØU�p½�$.

À�Ü·�Uþ§¦�E?\�¥Úå�§2�{~�

Outline

1 Å�U£Åð¤Å�U£Åð¤Ù¦/ª�³U

2 ÄU½nõ Work

�:ÄU½n�:XÄU½n

3 ³UÚå³U(k%å)

�Åå�³U³U­���$Ä���5�

4 Å�UÅð½Æ�:XÅ�UÅð½Æ�ÅX��m�üØC5üN¯K

5 �%X��ZF½n�ZF½n�%X¥.5å¤��õ

6 -E�-�-�%X¥�-E

7 é¡5�Åð½Æé¡5�Åð½Æ

Page 9: þ ðkd k JÑ René Descartes, 1637 Ô I 2. Gottfried Leibniz å vis viva …zimp.zju.edu.cn/~qchen/Teaching/Mechanics/Handout4.pdf · 2017-11-02 · Question: Big bang §t= 0 žU

��$Ä���5� → �Åå�/

V (x1)− V (x2) =

∫ x2

x1

Fdx

F = −dV

dx1

2mv2 + V (x) = E

=⇒ E ≥ V (x)

If E = E2 =⇒ x1 ≤ x ≤ x2

E1 ≤ E ≤ 0�§�åP$ÄE > 0�§��±∞

If E = E3,−∞ ≤ x ≤ x3 or x ≥ x4. (x3 ∼ x4�m�³^)

E ≥ E4,−∞ < x < +∞gd�åP$Ä� E = E1 �, x = x5§·�§4��:§

F (x5) = − dV

dx

∣∣∣∣x=x5

= 0 ØÉå

� x = x6 �§�k F (x6) = 0, ØÉå� E = E4 = V (x6) �§x6 ? v = 0§·�§�Ø­½

��$Ä���5�→�Åå�/

dx

dt= ±

√2 (E − V ) /m , −→÷± x��$Ä

t = ±√m

2

∫ x

x0

dx√E − V (x)

, −→�¦$Ä�m

t1→2 =

√m

2

∫ x2

x1

dx√E2 − V (x)

, F (x2) = − dV

dx

∣∣∣∣x2

< 0§$Ä��

t2→1 = −√m

2

∫ x1

x2

dx√E2 − V (x)

w,, t2→1 = t1→2

=⇒ ±Ï T = 2t1→2 =√

2m

∫ x2

x1

dx√E2 − V (x)

~: á��³²¥�$Ä

V (x) =

{0,∞,

−l/2 ≤ x ≤ l/2elsewhere

V x

V V

0V

/ 2l/ 2l x

T =

√2m

E

∫ l/2

−l/2dx =

√2m

El

E =1

2mv2 =⇒ T =

2l

v

Outline

1 Å�U£Åð¤Å�U£Åð¤Ù¦/ª�³U

2 ÄU½nõ Work

�:ÄU½n�:XÄU½n

3 ³UÚå³U(k%å)

�Åå�³U³U­���$Ä���5�

4 Å�UÅð½Æ�:XÅ�UÅð½Æ�ÅX��m�üØC5üN¯K

5 �%X��ZF½n�ZF½n�%X¥.5å¤��õ

6 -E�-�-�%X¥�-E

7 é¡5�Åð½Æé¡5�Åð½Æ

Page 10: þ ðkd k JÑ René Descartes, 1637 Ô I 2. Gottfried Leibniz å vis viva …zimp.zju.edu.cn/~qchen/Teaching/Mechanics/Handout4.pdf · 2017-11-02 · Question: Big bang §t= 0 žU

�:XÅ�UÅð½Æ

T − T0 = W +WS → �:XÄU½nWS = W�S +W��S

W�S = V0 − V, V (r)��ÅSå�³¼ê

=⇒ (T + V )− (T0 + V0) = W +W��S

= E − E0 = W +W��S�:XõU½n½õU�n

W = 0 :

1!�áNX2!d~r = 0, → å�^:vk £3!~Fext ⊥ d~r§å�Ù�A�^:� £p�R�

If W = 0,

1 W��S > 0§X�¿2 W��S < 0§X�Þå3 W��S = 0§Å�UÅð

�:XÅ�UÅð½Æ

�.5X¥§X�A^õU½n§LO\.5å9Ù�'³U

5¿1 å¤��õ W �ë�Xk'§ Så¤��õ�ë�

XÃ'2 K.E. �ë�Xk'3 ³U V (r) �ë�XÃ'Å�UÅð3��ë�X¥¤á§3,��¥�Uؤá

~~~4.2 n�:n:���²¡þ§ØO�Þ§¥m�:¼Ð�Ý~v0, ¦ü>�:�����Ç v.

0v

y)))µµµ ÄþÅðµmv0 = 3mvy

UþÅðµ12mv0

2 = 12mv

2y + 2 · 1

2mv2

=⇒ v2 =1

2v0

2 − 1

2

(v0

3

)2=

4

9v0

2

v =2

3v0

Outline

1 Å�U£Åð¤Å�U£Åð¤Ù¦/ª�³U

2 ÄU½nõ Work

�:ÄU½n�:XÄU½n

3 ³UÚå³U(k%å)

�Åå�³U³U­���$Ä���5�

4 Å�UÅð½Æ�:XÅ�UÅð½Æ�ÅX��m�üØC5üN¯K

5 �%X��ZF½n�ZF½n�%X¥.5å¤��õ

6 -E�-�-�%X¥�-E

7 é¡5�Åð½Æé¡5�Åð½Æ

�ÅX��m�üØC5![�²ï��O\�n

Time reversalµt→ −t

~F = md~v

dt= m

d(−~v)

d(−t)ü��:3�Åå�^eäkT-symmetry

�Åå ~F 3�m�üeØC§��ÞåKdu ~v UC�� CÒ"¤±k�Þå�§Øäk�m�üØC5 −→ L§Ø�_

�*�L§¥§ü�-Eo´�_� −→ [�²ï�n

÷*ÚOKØ�_ −→ �O\�n

不可逆(混合过程)

真空

气体

气体

Page 11: þ ðkd k JÑ René Descartes, 1637 Ô I 2. Gottfried Leibniz å vis viva …zimp.zju.edu.cn/~qchen/Teaching/Mechanics/Handout4.pdf · 2017-11-02 · Question: Big bang §t= 0 žU

Outline

1 Å�U£Åð¤Å�U£Åð¤Ù¦/ª�³U

2 ÄU½nõ Work

�:ÄU½n�:XÄU½n

3 ³UÚå³U(k%å)

�Åå�³U³U­���$Ä���5�

4 Å�UÅð½Æ�:XÅ�UÅð½Æ�ÅX��m�üØC5üN¯K

5 �%X��ZF½n�ZF½n�%X¥.5å¤��õ

6 -E�-�-�%X¥�-E

7 é¡5�Åð½Æé¡5�Åð½Æ

üN¯K

1rCr

2r2m

1mC1r

C2r

X㤫ü�:NX

mc = m1 +m2

~rc =m1~r1 +m2~r2

m1 +m2

m1d2~r1

dt2= ~f21 = −~f12 = −m2

d2~r2

dt2= ~F

=⇒ mcd2~rcdt2

= 0 = mcd~vcdt

=d~Pc

dt

ØÉå�§�%�!�$Ä£�,�k�%ÄþÅð¤

üN¯K (cont'd)

��%X§K ~rc = 0

~rc1 = ~r1 − ~rc = ~r1 −m1~r1 +m2~r2

m1 +m2=

m2

m1 +m2(~r1 − ~r2) =

m2~r

m1 +m2

~rc2 = ~r2 − ~rc = − m1~r

m1 +m2

d? ~r = ~r1 − ~r2 → �é £

~rc1 − ~rc2 = ~r =⇒ ~v =d~r

dt= ~v1 − ~v2 �é�Ý

rc1rc2

=m2

m1or ~rc1m1 +m2~rc2 = 0

�:��%�ål��þ¤�'

üN¯K (cont'd)

XXX m1 � m2§§§���ÄÄÄ m1 ���ééé m2 ���$$$ÄÄÄ� S X§�éu m2 ·��²Äë�X§m2  u�:§~r2 = 0, ~r1 = ~r§SX��.5X

.5X¥µd2~r

dt2=

d2 (~r1 − ~r2)

dt2=

d2~r1

dt2− d2~r2

dt2

=

(1

m1+

1

m2

)~F =

m1 +m2

m1m2

~F =1

µ~F

µ ≡ m1m2

m1 +m2� �z�þ§òÜ�þ

=⇒ µd2~r

dt2= ~F

µ ' m1 −→ @���þ m2 Øħ ^ µ �� m1§KSXCq�.5X

Page 12: þ ðkd k JÑ René Descartes, 1637 Ô I 2. Gottfried Leibniz å vis viva …zimp.zju.edu.cn/~qchen/Teaching/Mechanics/Handout4.pdf · 2017-11-02 · Question: Big bang §t= 0 žU

üN¯K (cont'd)

�%X¥µ

~vc1 =m2

m1 +m2~v, ~vc2 =

−m1

m1 +m2~v

E =1

2m1v

2c1 +

1

2m2v

2c2 + V (r) ←³UV

=1

2m1

m22v

2

(m1 +m2)2 +1

2m2

m21v

2

(m1 +m2)2 + V (r)

=1

2

m1m2

m1 +m2v2 + V (r)

E =1

2µv2 + V (r)

��±µ��m1§K�@�SX´.5X��¦�Å�U£�%X¥�¤£�w,ØU¦��%XÄþ¤=|^�z�þ§�òüN¯Kz�üN¯K>

üN¯K (cont'd)

ggg������ÖÖÖKKKµµµ

nN¯K�±�z¤üN¯K½Ù¦{ü¯Kíº

���ÖÖÖ���ááá

Laplace�û½Øg�£ÄuÚîåƤ↓

Poincare�Chaos → �R�A��5XÚ¥§Ð©����Cz¬��XÚ1�4�UC↓

intrinsic stochasticity → S��Å5

Outline

1 Å�U£Åð¤Å�U£Åð¤Ù¦/ª�³U

2 ÄU½nõ Work

�:ÄU½n�:XÄU½n

3 ³UÚå³U(k%å)

�Åå�³U³U­���$Ä���5�

4 Å�UÅð½Æ�:XÅ�UÅð½Æ�ÅX��m�üØC5üN¯K

5 �%X��ZF½n�ZF½n�%X¥.5å¤��õ

6 -E�-�-�%X¥�-E

7 é¡5�Åð½Æé¡5�Åð½Æ

�ZF½n (Konig's Theorem)

�KX→.5X§Kc��%X

~ri = ~rc + ~rci, ~vi = ~vc + ~vci, ~ai = ~ac + ~aci

T =1

2

∑imiv

2i , Tc =

∑i

1

2miv

2ci

=⇒ T =1

2

∑imi (~vc + ~vci)

2 =∑

i

1

2mi

(~v2c + ~v2

ci + 2~vc · ~vci)

=∑

i

1

2mi~v

2c + ~vc ·

∑imi~vci +

∑i

1

2mi~v

2ci

=1

2mc~v

2c +

∑i

1

2mi~v

2ci (

∑imi~vci = 0)

=1

2mc~v

2c + Tc

NXÄU = �%ÄU + NX�éu�%X�ÄU�� ���ZZZFFF½½½nnn£3�.5X¥��¤

£Äþ�/µNXÄþ=�%Äþ¤

Page 13: þ ðkd k JÑ René Descartes, 1637 Ô I 2. Gottfried Leibniz å vis viva …zimp.zju.edu.cn/~qchen/Teaching/Mechanics/Handout4.pdf · 2017-11-02 · Question: Big bang §t= 0 žU

²þ�/½n0

∑i

XiWi = X∑i

Wi = WX, Xi = X + δi∑i

X2iWi =

∑i

(X + δi

)2Wi = X2

∑i

Wi +∑i

Wiδ2i + 2X

∑i

δiWi

= WX2 +∑i

Wiδ2i

ëYµW =

∫W (~r) d3r, X =

∫W (~r)Xd3r

W∫W (~r)X2 (~r) d3r =

∫W (~r)

(X + δ

)2d3r

= X2

∫W (~r) d3r +

∫W (~r) δ2 (~r) d3r + 2X

∫W (~r) δ (~r) d3r

= WX2 +

∫W (~r) δ2 (~r) d3r

Outline

1 Å�U£Åð¤Å�U£Åð¤Ù¦/ª�³U

2 ÄU½nõ Work

�:ÄU½n�:XÄU½n

3 ³UÚå³U(k%å)

�Åå�³U³U­���$Ä���5�

4 Å�UÅð½Æ�:XÅ�UÅð½Æ�ÅX��m�üØC5üN¯K

5 �%X��ZF½n�ZF½n�%X¥.5å¤��õ

6 -E�-�-�%X¥�-E

7 é¡5�Åð½Æé¡5�Åð½Æ

�%X¥.5å¤��õ

�Ä ~ac 6= 0

.5å−mi~ac = ~F i

in

õWi =

∫~F iin · d~rci

W. =∑i

∫(−mi~ac) · d~rci

= −~ac ·∫ ∑

i

mid~rci = −~ac ·∫

d (mc~rcc) = 0

(∵ ~rcc = 0)

=⇒ �%X¥ÃI�Ä.5å¤��õ

~~~4.3 ÓEþ�<± v′ = 4 m/s ��é� Ç�cÚ���ÑÔN m = 1 kg§b�E± v0 = 2 m/s��Ç$Ľ·�§ü«�¹e<éÔN©O�õ �õº

)))µdÄþÅð§ Mu+m (v′ − u) = 0or

M (v0 + u) +m(v′ − u+ v0

)= (m+M) v0

=⇒ u = − mv′

m+M' −mv

M, m�M

If v0 = 0:

Tm − T 0m =

1

2m(v′ − u

)2 ' 1

2mv′2

TM − T 0M =

1

2Mu2 ≈

(mM

) mv′22

=m

M

(Tm − T 0

m

)�(Tm − T 0

m

)

Page 14: þ ðkd k JÑ René Descartes, 1637 Ô I 2. Gottfried Leibniz å vis viva …zimp.zju.edu.cn/~qchen/Teaching/Mechanics/Handout4.pdf · 2017-11-02 · Question: Big bang §t= 0 žU

If v0 6= 0:

TM − T 0M =

1

2M (v0 + u)2 − 1

2Mv0

2

=1

2Mu2 +Mv0u

≈Mv0u = −mv0v′ , |u| � v0

Tm − T 0m =

1

2m(v′ − u+ v0

)2 − 1

2mv0

2

' 1

2m(v′ + v0

)2 − 1

2mv0

2

=1

2mv′2 +mv′v0

ü���é'­�v0

v′§Ø�6uM

=⇒ ∆Tm+M '1

2mv′2

XXX^���%%%XXXµv0 = 0 =⇒ ∆T ' 12mv

′2, ÃIO�ÓE�$ÄG�

~~~4.4 1n�»�Ý(ºÑ��X��Ý)

�»��é/¡�Ç� v′§<Ñ/¥Úå�� v§³UV (∞) = 0d?À»�¨/¥�%X

1

2mv2 =

1

2mv′2 −GmME

RE=

1

2mv′2 −mgRE

¿©|^/¥ú=;��Ý1

2m (v + 29.8)2 −GmM�

R�= 0 →»�¨���%X

=⇒ v =

√2GM�R�

− 29.8 = 42.2− 29.8 = 12.4 km/s

v′2 = v2 + 2gRE = 12.42 + 11.22

=⇒ v′ ' 16.7 km/s

XJ�ÜÀ»�¨���%X§K�O9/¥�ÄUCz

Outline

1 Å�U£Åð¤Å�U£Åð¤Ù¦/ª�³U

2 ÄU½nõ Work

�:ÄU½n�:XÄU½n

3 ³UÚå³U(k%å)

�Åå�³U³U­���$Ä���5�

4 Å�UÅð½Æ�:XÅ�UÅð½Æ�ÅX��m�üØC5üN¯K

5 �%X��ZF½n�ZF½n�%X¥.5å¤��õ

6 -E�-�-�%X¥�-E

7 é¡5�Åð½Æé¡5�Åð½Æ

-E

�5-Eµ-�ÔN©m§ÃUþ��§Å�UÅð�ÄL§4á§:�> → ÄU!ÄþÅð

��5µ��kÅ�U��§=z�-EÔ�m�SÜUþ����5µ-�üÔNÜ3�å$ħÅ�U����

���Ä-EL§4á§åÀþ9�õØO§okÄþÅð

���---£££ééé%%%---EEE¤¤¤µµµhead-on collision

-�ü¥�ÝE÷� ~r1 − ~r2 ��(1) Ø �ã§Ð��ü¥�Ý�� v§Ð� u1, u2

m1u1 +m2u2 = (m1 +m2) v

ÀþIµ�åé m2

m1v −m1u1 = −Im2v −m2u2 = I

}=⇒ (u1 − u2) = I

(1

m1+

1

m2

)I = µ (u1 − u2) , µ =

m1m2

m1 +m2

Page 15: þ ðkd k JÑ René Descartes, 1637 Ô I 2. Gottfried Leibniz å vis viva …zimp.zju.edu.cn/~qchen/Teaching/Mechanics/Handout4.pdf · 2017-11-02 · Question: Big bang §t= 0 žU

�-£é%-E¤

(2) ¡E�ã§g¥mü¥�Ý���"�Ý v1, v2

(m1 +m2) v = m1v1 +m2v2

�å� m2 �Àþ J

J = m2v2 −m2v−J = m1v1 −m1v

}=⇒ J = µ (v2 − v1)

½Â e = J : I −→ ¡EXê

v2 − v1 = e (u1 − u2)m1u1 +m2u2 = m1v1 +m2v2

}=⇒

v1 =

m1 − em2

m1 +m2u1 +

(1 + e)m2

m1 +m2u2

v2 =(1 + e)m1

m1 +m2u1 −

em1 −m2

m1 +m2u2

e = 1 :

v1 =

m1 −m2

m1 +m2u1 +

2m2

m1 +m2u2

v2 =2m1

m1 +m2u1 −

m1 −m2

m1 +m2u2

-EL§¥�ÄU��

Tc =1

2µv2

=1

2µ (u1 − u2)2

-E�T ′c =

1

2µ (v2 − v1)2 =

1

2µe2 (u1 − u2)2

ÄU��

∆T = Tc − T ′c =1

2

(1− e2

)µ (u1 − u2)2

(1) e = 1µ���5§UÄþ�Åðm1 = m2: v1 = u2, v2 = u1§���Ý

-EL§¥�ÄU��

ifu2 = 0 :

m1 > m2 =⇒ v1 > 0§�¥ØUUC�¥��m1 < m2 =⇒ v1 < 0§�¥��¥��m2 � m1 =⇒ v1 ' −u1, v2 ' 0§�¥���£m2 � m1 =⇒ v1 ' u1, v2 ' 2u1§�¥��c?§

�¥¼2��Ý

T f2

T i1

=12m2v

22

12m1u2

1

=4m1m2

(m1 +m2)2 =4µ

m1 +m2=

4m1/m2

(1 +m1/m2)2

d(T f

2 /Ti1

)d (m1/m2)

= 0 =⇒ m1

m2= 1

=��þ-E§m2 ¼���ÄU§½ö`§� u2 = 0 �§m1

��C m2§m1 ¿��ÄU�õ

(2) e = 0µ����5-E§ÄU���õ

∆T = Tc − T ′c =1

2µ (u1 − u2)2 ,

(T ′c = 0

)-� v1 = v2 = vc =

m1u1 +m2u2

m1 +m2

éuâf-E�A§du E = Tc +1

2mcv

2c �

1

2mcv

2c

=⇒ =¦´����5§Ù�%�ÄU�جUC§Ïd �^�ÄU�´�%X£½Äþ¥%X¤¥�ÄU§½�éÄU

éu��þ m1 E· � m2§µ = 12m1,

Tc = 12µu

21 = 1

4m1u21 = oÄU��.

Page 16: þ ðkd k JÑ René Descartes, 1637 Ô I 2. Gottfried Leibniz å vis viva …zimp.zju.edu.cn/~qchen/Teaching/Mechanics/Handout4.pdf · 2017-11-02 · Question: Big bang §t= 0 žU

(3) 0 < e < 1µ���/

If m2 � m1, u2 = 0, K v1 = −eu1, v2 = 0

�¥£��Ý�-c�e�.

�¥�/¡-E�¡EXêÿ½µ

u1 =√

2gh0 , h =v2

1

2g

e =v1

u1=

√h

h0

Outline

1 Å�U£Åð¤Å�U£Åð¤Ù¦/ª�³U

2 ÄU½nõ Work

�:ÄU½n�:XÄU½n

3 ³UÚå³U(k%å)

�Åå�³U³U­���$Ä���5�

4 Å�UÅð½Æ�:XÅ�UÅð½Æ�ÅX��m�üØC5üN¯K

5 �%X��ZF½n�ZF½n�%X¥.5å¤��õ

6 -E�-�-�%X¥�-E

7 é¡5�Åð½Æé¡5�Åð½Æ

�-µ~v1�~u1ز1

�Ä�5-Eµm1~u1 +m2~u2 = m1~v1 +m2~v2

1

2m1u1

2 +1

2m2u2

2 =1

2m1v1

2 +1

2m2v2

2

If u2 = 0µm1~u1 = m1~v1 +m2~v2

1

2m1u1

2 =1

2m1v1

2 +1

2m2v2

2

1u 1v

2vx2m1m

b 12

� ~u1 ���� x ¶§-E¤3¡� x− y ²¡§K

m1u1 = m1v1 cos θ1 +m2v2 cos θ2

0 = m1v1 sin θ1 −m2v2 sin θ2

��ê'�-�õ§UC¤Oål§�UCÑ�� θ1, θ2

?�Ú§�Ä m1 = m2 = m§� u2 = 0:

~u1 = ~v1 + ~v2

u21 = v2

1 + v22

=⇒ ± ~u1 ��>���n�/§~v1 ⊥ ~v2

-E�üâf$Ä��R�§/¤XãÑ��.

ÿ� ~v1 =� ~v2

1v

2v

1u

散射圆

�±^Ñ��5©Û��þ£XP − P¤âf-E´Ä�5

入射质子

detector

Page 17: þ ðkd k JÑ René Descartes, 1637 Ô I 2. Gottfried Leibniz å vis viva …zimp.zju.edu.cn/~qchen/Teaching/Mechanics/Handout4.pdf · 2017-11-02 · Question: Big bang §t= 0 žU

Outline

1 Å�U£Åð¤Å�U£Åð¤Ù¦/ª�³U

2 ÄU½nõ Work

�:ÄU½n�:XÄU½n

3 ³UÚå³U(k%å)

�Åå�³U³U­���$Ä���5�

4 Å�UÅð½Æ�:XÅ�UÅð½Æ�ÅX��m�üØC5üN¯K

5 �%X��ZF½n�ZF½n�%X¥.5å¤��õ

6 -E�-�-�%X¥�-E

7 é¡5�Åð½Æé¡5�Åð½Æ

�%X¥�-E

oÄþ ~P = 01!�- (~u1, ~u2)→ (~v1, ~v2) → LabX¥.

~vc =m1~u1 +m2~u2

m1 +m2

~u1 = ~uc1 + ~vc, ~u2 = ~uc2 + ~vc

~v1 = ~vc1 + ~vc, ~v2 = ~vc2 + ~vc

=⇒ m1uc1 +m2uc2 = m1vc1 +m2vc2 = 0

vc2 − vc1 = e (uc1 − uc2)

=⇒{vc1 = −euc1vc2 = −euc2

�%X¥§-���Ý´Ù-c�Ý�−e�

∆T = Tc − T ′c =(1− e2

) 1

2

(m1u

2c1 +m2u

2c2

)=(1− e2

)T

e = 1 �§ÄUÅðe = 0 �§-�ÄU�Ü��§C�"

2!!!���---

m1~uc1 +m2~uc2 = m1~vc1 +m2~vc2 = 0

m1uc1 +m2uc2 = m1vc1 +m2vc2 = 0

vc2 − vc1 = uc1 − uc2 ���5

=⇒ vc1 = uc1, vc2 = uc2

2v2u

1v

1u

�%X¥§���5üÔN-��ÇØC§�k��UC

1v

2u

1u2m

1m

1m~~~4.5 ���üüü���AAA& ÿ ì m1 � 1 ( m2 �é � � � Ý © O � ~u1, ~u2,

m1 �� m2§m1 7 m2 �� ��Ñ ~v1§¦~v1.

)))µµµ ���5-E§e = 1

v1 =m1 − em2

m1 +m2u1 +

(1 + e)m2

m1 +m2u2 =

m1 −m2

m1 +m2u1 +

2m2

m1 +m2u2

' −u1 + 2u2

Alternatively§m1 ± |u1|+ |u2|��Ý7 m2 �7�±���Ç���Ñ=⇒ m1 �éu����Ç� |u1|+ |u2|+ |u2| = |u1|+ 2 |u2|.

Page 18: þ ðkd k JÑ René Descartes, 1637 Ô I 2. Gottfried Leibniz å vis viva …zimp.zju.edu.cn/~qchen/Teaching/Mechanics/Handout4.pdf · 2017-11-02 · Question: Big bang §t= 0 žU

?ë-E

M m m mO

u 3 2 1x

~~~4.6 ?ë-E§Ã�Þ�5§M > m§¦�w¬�ª�Ý

)))µµµ M − 3-Eµ

{Mu = Mu1 +mv11

2Mu2 =

1

2Mu2

1 +1

2mv2

1

=⇒

u1 =

M −mM +m

u

v1 =2M

M +mu

M±u1 < v1��ÝUYc?§3↔ 2 ���Ý=⇒ 2↔ 1 ���ݧm1±v1c?

M − 31�g-

u2 =

(M −mM +m

)2

u

v2 =2M

M +mu1 =

2M

M +m

M −mM +m

u < v1

?ë-E (cont'd)

m3±v2c? → 3↔ 2 ���ݧm2±v2c?§á�um1§m3·�.

M − 31ng-Eµ

u3 =

(M −mM +m

)3

u

v3 =2M

M +m

(M −mM +m

)2

u < v2

m3±v3 < v2 < v1��Ýc?M±u3 < v3��Ýc?

N�m�§��Ý©O�µ

uN =

(M −mM +m

)N

u, vN =2M

M +m

(M −mM +m

)N−1

u

· · · · · ·

v2 =2M

M +m

M −mM +m

u, v1 =2M

M +mu

Outline

1 Å�U£Åð¤Å�U£Åð¤Ù¦/ª�³U

2 ÄU½nõ Work

�:ÄU½n�:XÄU½n

3 ³UÚå³U(k%å)

�Åå�³U³U­���$Ä���5�

4 Å�UÅð½Æ�:XÅ�UÅð½Æ�ÅX��m�üØC5üN¯K

5 �%X��ZF½n�ZF½n�%X¥.5å¤��õ

6 -E�-�-�%X¥�-E

7 é¡5�Åð½Æé¡5�Åð½Æ

é¡5�Åð½Æ Symmetry and Conservation Laws

���ooo���ééé¡¡¡555ºººXÚ½5Æ3,«ö�eØC§KTXÚ½5ÆäkTé¡5

���mmm²²²£££ØØØCCC555µµµ�áNX�UþØ��mCz → UþÅð

���mmm²²²£££ØØØCCC555µµµ

B

'A As

B 'B

A

s

a b

�ÄA−Bm�^³V§K ∆V = ∆V ′

∆V = −~fB→A ·∆~s, ∆V ′ = −~fA→B · (−∆~s)

A′B = AB′

²£ØC5�¦ V + ∆V = V + ∆V ′

⇐⇒ ∆V = −~fB→A ·∆~s = ∆V ′ = ~fA→B ·∆~s∵ ∆~s ?¿§

=⇒ ~fB→A = −~fA→B

⇐⇒ ÄþÅð


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